10[z-(3z+11)+3]=2(z+4)

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Solution for 10[z-(3z+11)+3]=2(z+4) equation:


Simplifying
10[z + -1(3z + 11) + 3] = 2(z + 4)

Reorder the terms:
10[z + -1(11 + 3z) + 3] = 2(z + 4)
10[z + (11 * -1 + 3z * -1) + 3] = 2(z + 4)
10[z + (-11 + -3z) + 3] = 2(z + 4)

Reorder the terms:
10[-11 + 3 + z + -3z] = 2(z + 4)

Combine like terms: -11 + 3 = -8
10[-8 + z + -3z] = 2(z + 4)

Combine like terms: z + -3z = -2z
10[-8 + -2z] = 2(z + 4)
[-8 * 10 + -2z * 10] = 2(z + 4)
[-80 + -20z] = 2(z + 4)

Reorder the terms:
-80 + -20z = 2(4 + z)
-80 + -20z = (4 * 2 + z * 2)
-80 + -20z = (8 + 2z)

Solving
-80 + -20z = 8 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-80 + -20z + -2z = 8 + 2z + -2z

Combine like terms: -20z + -2z = -22z
-80 + -22z = 8 + 2z + -2z

Combine like terms: 2z + -2z = 0
-80 + -22z = 8 + 0
-80 + -22z = 8

Add '80' to each side of the equation.
-80 + 80 + -22z = 8 + 80

Combine like terms: -80 + 80 = 0
0 + -22z = 8 + 80
-22z = 8 + 80

Combine like terms: 8 + 80 = 88
-22z = 88

Divide each side by '-22'.
z = -4

Simplifying
z = -4

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